Wronskian vs. Determinant in Determining Linear Independence?

Click For Summary
The discussion centers on the relationship between the Wronskian and the determinant in determining linear independence. It is noted that if a row in a matrix can be zeroed out through Gaussian reduction, the determinant becomes zero, indicating dependence among the vectors. The Wronskian is highlighted as a specific type of determinant useful for assessing linear independence in the context of differential equations. There is a distinction made between the use of Wronskians for function spaces and determinants for vector spaces like Cartesian coordinates. Understanding these concepts is crucial for correctly identifying linear independence in different mathematical contexts.
kq6up
Messages
366
Reaction score
13
It seems to me that if a row is able to be zeroed out through Gaussian reduction that the determinate of that matrix would equal zero. Therefore, we know that at least one of equations/vectors that constructed the matrix was formed from the other two rows. That is -- that equation is dependent on the other two basis vectors.

Why do we need the Wronskian to determine this?

Thanks,
Chris Maness
 
Physics news on Phys.org
The Wronskian is a special type of determinant used to determine if a set of solutions to a differential equation is linearly independent:

http://en.wikipedia.org/wiki/Wronskian

See the section on "The Wronskian and linear independence".
 
Ok, is it that Wronskians are for function space where all the basis are formed by functions of x, where the determinants are for -- say -- {x,y,z} vectors in cartesian space?

Chris
 
I am studying the mathematical formalism behind non-commutative geometry approach to quantum gravity. I was reading about Hopf algebras and their Drinfeld twist with a specific example of the Moyal-Weyl twist defined as F=exp(-iλ/2θ^(μν)∂_μ⊗∂_ν) where λ is a constant parametar and θ antisymmetric constant tensor. {∂_μ} is the basis of the tangent vector space over the underlying spacetime Now, from my understanding the enveloping algebra which appears in the definition of the Hopf algebra...

Similar threads

  • · Replies 23 ·
Replies
23
Views
2K
  • · Replies 8 ·
Replies
8
Views
3K
  • · Replies 3 ·
Replies
3
Views
2K
  • · Replies 6 ·
Replies
6
Views
3K
Replies
1
Views
2K
  • · Replies 3 ·
Replies
3
Views
2K
  • · Replies 2 ·
Replies
2
Views
2K
  • · Replies 5 ·
Replies
5
Views
3K
  • · Replies 4 ·
Replies
4
Views
3K
Replies
2
Views
1K