The discussion focuses on finding older derivatives of the function y = (1/2)x^4 - (3/2)x^2 - x. The correct first derivative, denoted as y', is derived as y' = 2x^3 - 3x - 1. Participants clarify that the initial differentiation attempts contained errors, specifically in the calculation of the derivatives of the terms. The final derivative provided, y4 = 7, is incorrect and does not correspond to the proper differentiation process.
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Do you mean y = (1/2)x4 - (3/2)x2 - x?r-soy said:Q Find all older derivatives
y = X^4/2 = 3/2X^2 -X
What is y4 supposed to be? Since you have taken the derivative, this should be y'. Of the three terms you differentiated on the right side, only one is correct: d/dx[-(3/2)x2] = -3x. The other two terms have errors.r-soy said:y4 = 2X^2 - 3 x ^ 1 - 0
?r-soy said:y4 = 4X^1 - 3 -0
?r-soy said:y4 = 7