X-component of angular momentum, Lx, acting on |n,l,m>

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SUMMARY

The eigenvalue of the angular momentum operator Lx acting on the state |n,l,m> can be derived using the relationships between Lx, L+, and L-. Specifically, Lx can be expressed as Lx = (L+ + L-)/2. By applying this operator to the state |n,l,m>, one can determine the resulting eigenvalue. The relevant equations include Lz|n,l,m>=mhbar|n,l,m> and L|n,l,m>=l(l+1)hbar^2|n,l,m>.

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Homework Statement



I need to know what the eigen value of Lx would be if, Lx|n,l,m>.

Homework Equations



L+-=Lx+-iLy
L2=Lx2+Ly2+Lz2
Lz|n,l,m>=mhbar|n,l,m>
L|n,l,m>=l(l+1)hbar2|n,l,m>


The Attempt at a Solution



I have a mixed state I need to apply Lx tp, but I'm not sure how! If anyone known how to put this in terms of L, Lz, or L+-, I would really appreciate the help!
 
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Express Lx in terms of L+ and L -, then operate on |n,l,m> and see what you get.
 
Last edited:

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