1. The problem statement, all variables and given/known data What is the x-intercept of the line tangent to the curve x(t) = 3 + cos(∏t), y(t) = t^2 + t + 1, when t = 1? 2. Relevant equations Derivative, y=mx+b 3. The attempt at a solution To find the line tangent to the curve: d/dt = <-∏sin(∏t), 2t+1> at t=1 <-∏, 3> dy/dx = dy/du * du/dx = -3/∏ y=(-3/∏)x+b at t=1, <x,y>=<3,3> y-3 = (-3/∏)(x-3) y = -3x /∏ + 9/∏ +3 To find x-int. set y=0 so 0=-3x /∏ + 9/∏ +3 (-3 - 9/∏)(-∏/3)=x The answer is x=2. I am not sure where I went wrong.