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Homework Statement
y= l sin x l < absolute value of sinx
Homework Equations
The Attempt at a Solution
y= l sin x l= sinx, if x>0
-sinx, if x< 0
0, if x=0
I get that part, but when i draw the graph I don't get it
What about the graph don't you get?Homework Statement
y= l sin x l < absolute value of sinx
Homework Equations
The Attempt at a Solution
y= l sin x l= sinx, if x>0
-sinx, if x< 0
0, if x=0
I get that part, but when i draw the graph I don't get it
It should beCudi1 said:y= l sin x l= sinx, if x>0
-sinx, if x< 0
0, if x=0
Not necessarily. The graph is reflected across the x-axis when sin(x) < 0, which happens when -pi < x < 0, or when pi < x < 2pi, and a bunch of other intervals.k got it, so when x<0 it gets reflected across the x axis
That's how you need to look at it. It's not just when x >= 0 or x < 0., for the other values since we are dealing with absolute value, an aboslute value of a negative is positive. Thanks, only reason I got confused is when you put it in from sinx, if sinx>=0 and when sinx<0 thanks