MHB Y=-X if X ~ Ber(1/4): Solving the Mystery

[Dustinsfl]

If \(Y = -X\) and \(X\sim Ber(1/4)\), then what is Y?

I know that
\[
X\sim
\begin{cases}
1 - p, & x = 0\\
p, & x = 1
\end{cases}
\]
where \(p = 0.25\) in this case. What is the negative of \(X\) though. It doesn't make any sense making the probabilities negative.

 

[Jameson]

I'm not confident in this answer but I would consider this to also follow a Bernoulli distribution by the following:

$Y\sim
\begin{cases}
1 - p, & y = 0\\
p, & y = -1
\end{cases}$

You should look up random variable transformations and maybe you can find some examples with discrete transforms. The examples that come to mind I've done in the past year have all been for continuous distributions and involve using the CDF.

 

[zzephod]

I'm not confident in this answer but I would consider this to also follow a Bernoulli distribution by the following:

$Y\sim
\begin{cases}
1 - p, & y = 0\\
p, & y = -1
\end{cases}$

You should look up random variable transformations and maybe you can find some examples with discrete transforms. The examples that come to mind I've done in the past year have all been for continuous distributions and involve using the CDF.

That is the correct distribution, but it is not Bernoulli. A RV with a Bernoulli distribution takes only the values 0 or 1.

Given dwsmiths history of accuracy of posting questions I would not be supprised if what he was really asked for was the distribution of $Y=1-X$

.

 

[chisigma]

That is the correct distribution, but it is not Bernoulli. A RV with a Bernoulli distribution takes only the values 0 or 1.

Given dwsmiths history of accuracy of posting questions I would not be supprised if what he was really asked for was the distribution of $Y=1-X$

.

Your observation is not particularly useful from a practical point of view. Let's suppose to have two independent variables X and Y with exponential distribution and we want to find the distribution of the variable Z = X - Y. It is clear that it is necessary to determine the distribution of the variable - Y that will still exponential only instead of y appears -y and its domain will include all the $y \le 0$. Same problem of course if X and Y have Bernoulli distribution ...

Kind regards

$\chi$ $\sigma$

 

[Dustinsfl]

Given dwsmiths history of accuracy of posting questions I would not be supprised if what he was really asked for was the distribution of $Y=1-X$

.

Well, I can tell you are incorrect with your hypothesis.