Yet another maxwell boltzman question

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The discussion focuses on the Maxwell-Boltzmann distribution, specifically addressing the calculation of the average velocity in one dimension, denoted as \(\langle v_{x}\rangle=0\). The user presents the modified Maxwell-Boltzmann distribution function for one-dimensional velocity as \(f(v_{x})=\sqrt{\frac{m}{2\pi kT}}e^{-\frac{mv_{x}^{2}}{2kt}}\) and attempts to evaluate the integral \(\langle v\rangle=\int_{0}^{\infty}vf(v)dv\). The key conclusion is that the integration limits must be adjusted to range from \(-\infty\) to \(+\infty\) to account for the possibility of negative velocities, which is essential for correctly calculating the average velocity.

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I have posted a few questions on maxwell Boltzmann distribution, the problem this time is show:

\langle v_{x}\rangle=0

I believe the modified maxwell-boltz distrib. for one dimensional case is:

f(v_{x})=\sqrt{\frac{m}{2\pi kT}}e^{-\frac{mv_{x}^{2}}{2kt}}

My thinking was that simple plug it into the formula:

\langle v\rangle=\int_{0}^{\infty}vf(v)dv

and the integral should evaluate to 0 but the above clearly doesn't evaluate to 0.

Any advice on how to approach this problem is appreciated.
 
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The problem is not dealing with v but instead with vx, which can be negative. The integration limits should be from -∞ to +∞, not 0 to +∞.
 

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