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Introductory Physics Homework Help
Solving Part B of e=1500*18/(1.3x10^11 x 0.000452389)
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[QUOTE="calculator20, post: 6488668, member: 161666"] [B]Homework Statement:[/B] A vertical steel cable of diameter 24 mm and of length 18 m supports a weight of 1500 N attached to its lower end. Calculate a) the tensile stress in the cable, b) the extension of the cable, c) the elastic energy stored in the cable, assuming its elastic limit has not been reached. YM steel is 1.3x10^11 [B]Relevant Equations:[/B] E = FL/eA I’m fine with part a, answer 3.3 x10^6 but I’m getting 0.00045 for part b when it should be 2.8x10^-4, what am I missing? e = (1500x18)/(1.3x10^11 x 0.000452389) [/QUOTE]
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Introductory Physics Homework Help
Solving Part B of e=1500*18/(1.3x10^11 x 0.000452389)
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