The discussion revolves around estimating the elastic limit of a wire in the context of Young's Modulus. The original poster seeks clarification on whether the elastic limit refers to the mass applied when the limit is reached.
The discussion is progressing with participants clarifying the relationship between mass, force, and stress. There is an acknowledgment of the need to calculate stress at the yield point, and guidance has been provided regarding the units and calculations involved.
Participants are discussing the properties of the wire and the need for specific measurements, such as the cross-sectional area and diameter in SI units, to perform the calculations accurately.
Looks then like your plotting mass (presumably a mass hanging down on the wire, yielding a weight/force unit) versus extension.. You want to find the stress at yield. What is it? Are the properties of the wire given?ZedCar said:Thanks PhanthomJay, it's mass / grams on the y-axis and extension / mm on the x-axis.
PhanthomJay said:Looks then like your plotting mass (presumably a mass hanging down on the wire, yielding a weight/force unit) versus extension..
PhanthomJay said:You want to find the stress at yield. What is it? Are the properties of the wire given?
Yes, excellent. And I'm sure you know that a N/m^2 is called a 'pascal' for short.ZedCar said:Yes, that's right.
Ah, I see what you mean! I need to find the stress at the yield point.
So I'll obtain the applied force by using the mass (in kg) at which the elastic limit is reached and multiply this by 9.81 (acceleration due to gravity). Then divide this number by the cross sectional area of the wire. Ensuring when calculating the cross sectional area of the wire the diameter is in the SI unit of the metre.
So the final figure for the estimation of the elastic limit would be in the units of N/m2
PhanthomJay said:Yes, excellent. And I'm sure you know that a N/m^2 is called a 'pascal' for short.