Yukawa Potential: Find Value of Parameter 'a

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Homework Help Overview

The discussion revolves around the Yukawa potential and specifically the parameter 'a'. Participants express confusion regarding the value of 'a' and its significance in the context of the problem.

Discussion Character

  • Exploratory, Assumption checking

Approaches and Questions Raised

  • Participants attempt to clarify the meaning of the parameter 'a', with some suggesting it might relate to the radius of gold. Others question the clarity of the problem statement and the rendering of symbols.

Discussion Status

There is an ongoing exploration of the parameter 'a', with some participants indicating that the problem statement may provide the value explicitly. However, there is no clear consensus on its interpretation, particularly regarding the symbol for angstrom.

Contextual Notes

Participants note potential issues with the rendering of symbols in the problem statement, which may contribute to the confusion regarding the parameter 'a'.

MaestroBach
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Homework Statement
Given in the picture
Relevant Equations
None
So this is the problem:
f506TxI.png

My only point of confusion right now is in what the value of a is... I'm having trouble finding it anywhere, and online stuff about the yukawa potential just states that it's a parameter.

Thanks for any help!

Edit: It might be worth noting that gamma equals kq1q2.
 
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Try reading the problem statement more carefully.
 
vela said:
Try reading the problem statement more carefully.

I guess I should have stated that my only guess is that it's the radius of gold, based on what it's saying, but I'm not confident in my guess.
 
I'm not sure how you're missing it, but the problem statement explicitly tells you the value of ##a##.
 
vela said:
I'm not sure how you're missing it, but the problem statement explicitly tells you the value of ##a##.
Oh wait.. is that A an angstrom??

Edit: I guess I really haven't seen the symbol for an angstrom in a while... I thought it was some special value lol, thanks for dealing with this
 
MaestroBach said:
Oh wait.. is that A an angstrom??

Edit: I guess I really haven't seen the symbol for an angstrom in a while... I thought it was some special value lol, thanks for dealing with this
Yes, but in your defense the symbol was badly rendered. It should've been Å.
 
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