Zeeman effect after a Stern-Gerlach experiment

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SUMMARY

The discussion centers on the interaction of particles with a Stern-Gerlach apparatus and the subsequent observation of the Zeeman effect. It is established that when particles with well-defined orbital and spin angular momentum are selected, no Zeeman splitting occurs due to the defined quantum number j. The conversation highlights the necessity of exciting atoms to an excited state manifold to observe Zeeman splitting, as ground states do not exhibit degeneracy. The importance of ensuring the excited state lifetime exceeds the time taken for particles to exit the Stern-Gerlach apparatus is also emphasized.

PREREQUISITES
  • Understanding of Stern-Gerlach apparatus functionality
  • Knowledge of Zeeman effect and its types, particularly the anomalous Zeeman effect
  • Familiarity with quantum numbers, specifically orbital angular momentum (l), total angular momentum (j), and magnetic quantum number (m_j)
  • Concept of excited state manifolds in atomic physics
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  • Research the principles of the Stern-Gerlach experiment and its applications in quantum mechanics
  • Study the anomalous Zeeman effect and its implications in spectroscopy
  • Explore the concept of excited state lifetimes and their significance in atomic transitions
  • Investigate experimental setups for observing Zeeman splitting in various atomic systems
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Physicists, quantum mechanics students, and researchers interested in atomic physics and experimental techniques for observing quantum phenomena.

svletana
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Let's say you take a beam of particles and pass it through a Stern Gerlach apparatus and you select one of the outgoing beams, therefore collapsing the wavefunction to certain values of orbital angular momentum and spin angular momentum.

If you performed the Zeeman experiment on that beam, I'm assuming you wouldn't see any splitting because the particles in this beam have very well defined orbital and spin angular momentum? Assuming they all have the same quantum number n.

For example in the anomalous Zeeman effect the splitting occurs from the quantum number m_j, where j is the total angular momentum, correct? So since we have a very well defined value for j, there shouldn't be any splitting in that case.

Is this reasoning correct?
 
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I would like to make an attempt to answer this question, but I don't know that this answer is necessarily correct. First of all, presumably a magnetic field is applied in the same direction as the inhomogeneous field of the Stern Gerlach apparatus to try to cause a splitting of the levels. One question I have is, can we assume the atoms from the Stern-Gerlach apparatus are in an excited state? Assuming they are, the different ## m_j ## or ## m_s ## will be separated by the Stern-Gerlach apparatus, so that one portion of the split beam consists of only one ## m_j ## or one ## m_s ##. It is somewhat of a puzzle how the Zeeman effect is going to be observed=at least for me=normally the Zeeman effect is observed by having an arc lamp placed in a magnetic field to create the splittings. The discharge (arc lamp) is necessary because that is the easiest way to get excited states and observed spectral lines. In the Stern Gerlach apparatus, I don't know that you have a sufficient number of excited states. Presuming that you do, I think there could be a splitting of the levels of the lower state, and some Zeeman effect could then be observed, but an experiment such as this would need to have sufficient excited states. Perhaps someone with more expertise in this area could help to fully answer this question. @vanhees71 Might you have an input?
 
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svletana said:
For example in the anomalous Zeeman effect the splitting occurs from the quantum number mjm_j, where j is the total angular momentum, correct? So since we have a very well defined value for j, there shouldn't be any splitting in that case.
Charles Link said:
can we assume the atoms from the Stern-Gerlach apparatus are in an excited state?
That's a good point.
According to the abstract of this paper, Zeeman splitting can be observed in the fluorescence emission from a group of atoms/molecules by first exciting those atoms/molecules to some excited state manifold. Thus, if you want to run the atoms through a Stern-Gerlach separator first before observing the emission from one of the output channels, you need to ensure that the lifetime of the excited manifold is longer than the time the atoms take starting from excitation to the output channel.
I doubt though if one can do this experiment by observing the absorption from the ground state (hence eliminating the need of excitation) since no ground state is degenerate and thus won't split under whatever perturbation.
 
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blue_leaf77 said:
That's a good point.
According to the abstract of this paper, Zeeman splitting can be observed in the fluorescence emission from a group of atoms/molecules by first exciting those atoms/molecules to some excited state manifold. Thus, if you want to run the atoms through a Stern-Gerlach separator first before observing the emission from one of the output channels, you need to ensure that the lifetime of the excited manifold is longer than the time the atoms take starting from excitation to the output channel.
I doubt though if one can do this experiment by observing the absorption from the ground state (hence eliminating the need of excitation) since no ground state is degenerate and thus won't split under whatever perturbation.

Great Answer, thank you! The answers took a turn I did not expect :)
 
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