Zero as an element of an eigenvector

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SUMMARY

The discussion centers on the conditions under which a zero can appear as an element of an eigenvector. Specifically, when the zero is the last element, the matrix can be partitioned into a form that separates the eigenvector equations into two distinct parts: ##Ax = \lambda x## and ##v^T x = 0##. This indicates that the last column of the matrix does not influence the eigenvector equations directly. The inquiry also seeks methods to ascertain the presence of a zero in an eigenvector without explicit calculation.

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Quick question on eigenvectors;

Are there any general properties of a matrix that guarantee that a zero will or will not appear as an element in an eigenvector?

Thank you!
 
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Suppose the zero is the last element of the eigenvector. Then you can partition the matrix and write
##\begin{bmatrix} A & u \\ v^T & s \end{bmatrix}\begin{bmatrix} x \\ 0 \end{bmatrix} = \lambda
\begin{bmatrix} x \\ 0 \end{bmatrix}## where ##u## and ##v## are vectors and ##s## is a single matrix element.

Multiplying out you get the two equations ##Ax = \lambda x## and ##v^t x = 0##. Interestingly, the last column of the original matrix doesn't appear in those equations.
 
Thank you for your reply!

Is there a way to determine from the matrix whether a zero will appear without calculating the eigenvector explicitly?
 

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