Zero-momentum frame - total momentum in this frame

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SUMMARY

The discussion focuses on calculating the total kinetic energy of reactants in the center-of-mass frame for a non-relativistic scenario involving two particles, x and X. The derived formula for total kinetic energy is T* = μTx/mx, where mx is the mass of particle x and μ is the reduced mass of x and X. Participants express confusion regarding the second part of the problem, specifically about the interpretation of p*, which is suggested to represent the momentum of the incoming particle rather than the total momentum, which should indeed be zero in the zero-momentum frame.

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Homework Statement



Assume that all particles are non-relativistic, that the target X is initially at rest,
and that x has kinetic energy Tx in the laboratory frame. Show that the total kinetic
energy of the reactants in the centre-of-mass frame is given by T* = μTx/mx, where mx is
the mass of particle x and μ the reduced mass of x and X. Also obtain an expression for
p* in terms of T* and μ.


Homework Equations



I have completed the first part of this question without a problem. The second part, requiring p* to be found doesn't make sense to me. Surely the total momentum in the zero-momentum frame should be zero? Or is it expecting a different quantity?


The Attempt at a Solution



First part done. Second part - don't know what it is asking.
 
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I agree. The problem isn't clear. One possible interpretation is that p* is the momentum of the incoming particle - as opposed to total momentum - as seen in the center of mass ref. frame.
 

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