Recent content by 4Phreal

It's a problem because we don't have that data point on the graph? I'm almost certain the answer for the 50 kΩ is 0.0

Oh sorry, the graph is for IB = 10 µA, 20 µA, 30 µA, ... , 80 µA.

Something like this? I kind of doubt that I have not been given sufficient information to answer the question without finding some obscure characteristics. But I also clearly have no idea what I'm doing, so my doubts don't hold much weight

What kind of characteristics? For the 2N3904 NPN transistor, when the base is more positive than the emitter by 0.6 volts (for the silicon devices) current will flow from the base to the emitter. When this base current IB is sufficiently large, the transistor is “turned on”. A current of 1 mA...

Homework Statement Consider a 2N3904 NPN transistor in a circuit. Treat the lightbulb as a 100 ohm resistor. For different values of R, what is the current through the lightbulb? Enter two digits rounded to the nearest 0.1 amps. If R=500 ohms, the current through the lightbulb is: If R=5...

Homework Statement An inductor is connected to a 20.0-Hz sinusoidal power supply that produces a 50.0-V peak voltage. What inductance is needed to keep the instantaneous current in the circuit below 77.4 mA?Homework Equations X(L)min = V(rms)/I(rms) I(rms) = I(max)/√2 X(L) = 2pi*f*LThe...

N is the number of turns, and I suppose since this isn't a solenoid that N=1

Homework Statement Here is the prompt: http://i.imgur.com/GsZck8J.jpg Homework Equations E(max) = NABw = 2pi*NABf The Attempt at a Solution E(max) = NABw = 2pi*NABf = NA*B(nought)*2pi*f 1.50 / (NA*B(nought)*2pi) = f f = 1.50 / N / ((2.50/100)^2*pi) / 0.109 / (2pi) The...

Homework Statement Here is the prompt: http://imgur.com/FTFz0fZ Homework Equations Magnetic flux = ∫B dot dA Net Flux for closed surface = 0 The Attempt at a Solution For part a: magnetic flux = (7.74 ^i + 4 ^j + 3 ^k)T * (0.254 m)^2 ^i = 7.74 T *...

Thanks! For some reason, the answer was positive instead of negative, but maybe that was just in the way the question was phrased.

I got the second 3 because I thought that (^i + ^j + ^k) divided by sqrt(3) equalled the velocity, so to get each individual part I divided by 3. But what you're saying is that they each individually equal 3.70E6 divided by sqrt(3), so there's no need to divide by that 3? In my determinant...

I'm familiar, I just don't know how to turn (i+j+k)/sqrt(3) into i, j, and k individually to perform the cross product. Is my attempt in the previous post how I would do it?

Right, um, but I don't know what the phrase in the problem that states the velocity vectors actually means (because I'm dumb), so I don't know what those are. Could you please explain what that phrase means? Here is my attempt: http://imgur.com/5C7Z648

1. Here is the prompt: http://imgur.com/mfbPidG 2. F = qv x B 3. At first this seemed like a simple cross product problem, and it probably still is, but I'm really confused as to what "3.70E6 m/s/ in the (i+j+k)/sqrt(3) direction" means, so I don't know how to set up my problem anymore. Could...

Homework Statement http://imgur.com/XXPWbCN Homework Equations ∑ ΔV (closed circuit) = 0 ∑ I (in) = ∑ I (out) The Attempt at a Solution So I know that the sum of the currents entering any junction in a circuit must equal the sum of the currents leaving that junction, and that the...