Homework Statement
There is a joint system of rods and masses.We need to set up Lagrangian.
Homework Equations
L= T-V , T = Kinetic energy , V = Potential energy
The Attempt at a Solution
Hey what should we take as the zero of potential. So does the Lagrangian depend on the zero...
OK if we are given the following first order rxn:
2N_2O_5 - > 4NO_2 + O_2
The rate constant is k. Now how would we express the rate law for the decomposition of N_2O_5.
- d[N_2O_5]/dt = k[N_2O_5]
OR
- d[N_2O_5]/dt = 2k[N_2O_5]
I think it is the latter but I see all books use...
I had been reading Feynman lectures , and in it he has shown an argument which proves that E field inside an empty cavity of a conductor is zero.OK. Now he says a similar argument can be used to show that if there is some charge in a cavity of a conductor than the field outside must be zero...
Actually, there are so many equilibria in this solution I can't figure out what will contribute and the assumption I made(given above) seems to give a wrong answer.
Homework Statement
50ml of 0.10M Na_3PO_4 + 50ml of 0.10M NaH_2PO_4
For H_2CO_3:
Ka_1 = 7.5 * 10^{ - 3}
Ka_2 = 6.2 * 10^{ - 8}
Ka_3 = 1.0 * 10^{ - 12}
Homework Equations
The Attempt at a Solution
Since K_h of Na_3PO_4 > > Ka_2 , I considered only hydrolysis of Na_3PO_4...
Homework Statement
A single electron with de Broglie wavelength \lambda passes through a slit of width d = 2\lambda. The electron can then strike a flourescent screen. What will be observed on the screen?
a) A diffraction pattern
b) A single flash has if the electron had moved in a straight...
To notice patterns you need very thin slits, if you have thick slits you won't be able to notice any change since construction destruction all occur so close together.
When we say heat released in a circuit is i^2 RT , who/what is the cause of this energy loss; is it the battery mechanism? Since work done on charge in the circuit by E field is zero, the only other force seems to be the battery mechanism, right? But in textbooks there is so much implication...