Recent content by @bhishek

Thanks once again.

Thank you,for explaining. Is this type of shielding used anywhere?

If that is the case than two conductors of any shape having an electrical path between them will have nil electric field between them when placed inside an electric field. Can we stretch the logic that far??

But the Faraday's cage is a closed one. Will the same principal be applicable to an open lid conductor also?? Thank You for the replies.

Why??

Suppose a constant electric field exists in space as shown in the file and a open lid cube type conductor is brought inside the field. What would be the electric field in the question marked area. Would it be zero or equal to original electric field.

That solves the problem. :D

If the surface is friction less then why should there be any extension in spring. Shouldn't the spring be able to pull the block m2 without any extension?

In the same special case with no relative motion if we put m1=m2 and F2=0 (the surface is friction-less, I forgot to mention it earlier) then the extension in the spring comes to F1/(2*k) Then how could there be extension when there is no friction acting on the masses?

Thanks Thank you. I noticed were I was wrong. In this case the eqn would be F1-kx = m1*a kx- F2 = m2*a Solving we would get x= (m2*F1+ m1* F2)/(k)(m1+m2)

Two masses m1 and m2 are connected by by spring of spring constant k. If two forces F1 and F2 acts on the two masses respectively in mutually opposite direction (i.e. outwards) what would be the extension in the spring and the acceleration of the two masses. I think that if assuming F1>F2 then...