Recent content by Byeonggon Lee

  1. Byeonggon Lee

    Is the converse of this theorem true or not?

    Thanks. Definitely better to use the definition than contrapositive.
  2. Byeonggon Lee

    Is the converse of this theorem true or not?

    Yes you're right. I edited the post. converse of the theorem: $$ \lim_{n\to\infty} a_n = 0 \Longrightarrow \lim_{n\to\infty} |a_n| = 0$$ I tried to prove it by using contrapositive contrapositive of the converse: $$ \lim_{n\to\infty} a_n \neq 0 \Longrightarrow \lim_{n\to\infty} |a_n| \neq 0$$ I...
  3. Byeonggon Lee

    Is the converse of this theorem true or not?

    This theorem is from the stewart calculus book 11.1.6 If $$ \lim_{n\to\infty} |a_n| = 0$$, then $$\lim_{n\to\infty} a_n = 0$$ I wonder whether converse of this theorem true or not
  4. Byeonggon Lee

    B 1 = -1, which part of this proof is wrong?

    Of course 1 isn't same as -1. This proof must be wrong but I can't find which part of this proof is wrong. Could you help me with this problem? (1)$$1 = \sqrt{1}$$ (2)$$= \sqrt{(-1)(-1)}$$ (3)$$= \sqrt{(-1)} \cdot i$$ (4)$$= i \cdot i$$ $$=-1$$
  5. Byeonggon Lee

    Definite integral of step function

    I need to prove whether this expression is true or false: ## \sum\limits_{k=1}^{n}\int_{k-1}^{k}[x]dx = \frac{n(n-1)}{2} ## I'm so confused because as I know, definite integral is possible only when the target function is continuous in closed interval. In this case, function ##[x]## should be...
  6. Byeonggon Lee

    ##\int\frac{2x+6}{(x-1)(x+1)^2} dx## ?

    Unfortunately my book seems extremely disorganized ... no details about this. Only this theorem exists in the corner of a page. Thanks I read the article in purple math, and see some videos in youtube.
  7. Byeonggon Lee

    ##\int\frac{2x+6}{(x-1)(x+1)^2} dx## ?

    Thanks for replying ! My book also introduced partial fraction decomposition which is ##\frac{1}{AB} =\frac{1}{B-A}(\frac{1}{A}-\frac{1}{B})## But this following expression is so complicated that I can't apply partial fraction decomposition. ##\frac{2x+6}{(x−1)(x+1)^2}## Could you explain to...
  8. Byeonggon Lee

    How to [itex]\int{\frac{-2x+20}{2\sqrt{-x^2+20x}}}dx[/itex]

    You can also use u-substitution as phion said## \int\frac{-2x+20}{\sqrt{-x^2+20}}dx ## As you can see -2x+20 is derivative of -x^2+20 And if you substitute -x^2+20 with variable such as t, then the problem becomes simpler ## t=-x^2+20x ## ## \frac{d(t)}{dt} = \frac{d(-x^2+20x)}{dt} ## ##...
  9. Byeonggon Lee

    ##\int\frac{2x+6}{(x-1)(x+1)^2} dx## ?

    Hi I'm currently doing 'integral by substitution' part in a book. Although it is integral by substitution part, some exercises are solved using reduction of fraction and integral, without substitution. (Actually I can't solve some exercises if I use substitution and the book's explanation also...
  10. Byeonggon Lee

    Should I memorize all these trigonometric integrals?

    I only memorized these trigonometric differential identities : `sin(x) = cos(x) `cos(x) = -sin(x) because I can convert tan(x) to sin(x) / cos(x) and sec(x) to 1 / cos(x) .. etcAnd there is no need to memorize some integral identities such as : ∫ sin(x) dx = -cos(x) + C ∫...
  11. Byeonggon Lee

    Solving Cos4x + Sin4x = 1: Can I Sqroot Both Terms?

    From the definition of trigonometric function cos=x/r sin=y/r From the Pythagorean theorem r^2=x^2+y^2 cos^4(x) + sin^4(x) =(x^4+y^4)/r^4 =((x^2+y^2)^2-2x^2y^2)/(r^4) =(r^4-2x^2y^2)/r^4 !=1
  12. Byeonggon Lee

    Good and easy mathematical logic book for computer science

    Hello I recently noticed that mathematical logic is related to computer science. I haven't studied math in university yet I'm not good at math and Since I'm not a native English speaker some English is hard to me. Is there any good and easy book which describes mathematical logic used in...
  13. Byeonggon Lee

    Proof of (p ⇒ q) =(¬p ∨ q) in Mathematical Logic

    Hi :smile: I am studying mathematical logic by a pdf file. But there is no proof about this therorem so I don't understand.. How to prove this?
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