Recent content by Calcifur

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    Imperial-Metric Unit conversion for Magnetic Field Gradiometer?

    Hi Charles, I understand it now! Very many thanks for coming back to me, your response was clear and informative. Once again, very much appreciated. Calcifur
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    Imperial-Metric Unit conversion for Magnetic Field Gradiometer?

    Hi all, I have a question which I think should be a simple solve for most people but I cannot seem to get my head around it. It is a common case in geophysical surveying that a magnetic field vertical gradiometer might be used. This instrument uses two magnetometers separated by a known...
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    Penetration of falling object into sediment (after water)

    Thanks anorlunda. Yes, as I told Dr. Courtney above, I actually keep getting directed to military papers on ballistics regularly, so this may well be my most useful source of research (despite not all of my object being bomb or bullet shaped) .
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    Penetration of falling object into sediment (after water)

    Dr. Courtney, once again, thanks for your response. I appreciate you directing me towards the "crater depth" research. I'm sure it will undoubtedly prove to be useful to me. If, as you say, modelling the problem, is too complex and costly (I doubt my company would provide me with the funding...
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    Penetration of falling object into sediment (after water)

    Thanks for your input here A.T. It does not surprise me about the sediment behavior. I imagine with Clay, the behavior would be different though in comparison to non-cohesive soils such as sand and gravel ? Anorlunda, thanks for your points. I totally agree. Like I said , this research is...
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    Penetration of falling object into sediment (after water)

    Hi All, Long time absentee from the forums hoping for some direction in my new research. I've been tasked to look into the stages of motion of objects (dropped from various heights), hitting a body of water (of various depths) and eventually hitting the seabed (of various sediment types). I am...
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    How can Helium 4 be a Boson and Helium 3 be a Fermion?

    Hi akhmeteli, Thank you for your response. I think its safe to assume that the text I was reading was referring to the first definition for Bosons then. Thanks for your references too. I will investigate further.
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    How can Helium 4 be a Boson and Helium 3 be a Fermion?

    Hi mfb, Thank you so much for answering each question individually. You have really helped me to get things straight in my head so I really appreciate it! Calcifur
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    How can Helium 4 be a Boson and Helium 3 be a Fermion?

    Hi Tom, Thanks for your response but I think I need the response in simpler terms. So are you saying that due to He 3 lacking a neutron its total spin cannot cancel to zero? Is it just a fundamental definition that Fermions have half spin and Boson's have integer spin? And does that mean...
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    How can Helium 4 be a Boson and Helium 3 be a Fermion?

    Hi there, Just a quick question which I'm sure I'm over complicating in my head.:confused: I've read that Helium 4 is a Boson because it has 0 spin and that Helium 3 is a Fermion because it has 1/2 spin. Is this right? I don't see how whole atoms can be associated with fundamental particle...
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    Need help manipulating absorption spectroscopy data please

    No takers huh? If anyone is having trouble understanding my problem please let me know or ask any questions. Many Thanks
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    Need help manipulating absorption spectroscopy data please

    Hi guys, So my project partner and I are struggling to solve a problem with our laser spectroscopy data for rubidium isotopes and I thought it may be a good idea to see if you could help us. If you take a look at the attached image you will see that the blue line shows our doppler free...
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    Making sense of Differentiation in Thermodynamics

    Ok, I think I finally understand it now! :approve: Thanks to everyone who gave their input! I think I was overcomplicating it!
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    Making sense of Differentiation in Thermodynamics

    Can it be done like this? The way I see it is you have to treat the differential of pV^{\gamma} as two separate differentials and by that I mean: \frac{d(pV ^{\gamma})}{dp}=V^{\gamma} and \frac{d(pV^{\gamma})}{dV}=p({\gamma}V^{\gamma-1}) Which can be reformed so that...
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    Making sense of Differentiation in Thermodynamics

    So when you differentiate V^{x}, you must multiply the differential of V^{x} with the differential of V alone? Can anyone tell me what rule this is? I understand what happens, I'm just struggling to understand why. Many thanks.
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