Yes, the voltage across the capacitor starts from zero and starts rising after around 12V it decreases the rate at which it ascends. The wiggly line was just a conductor bent. I do not have a reason why though. My thinking goes that it increases the magnetic field so that the compass needle...
The wiggly wire was in series the resistor acts as a light bulb. I believe we only used the compass to analyze the magnetic field produced in the circuit.
The connection when it was charging was like this: I do not know the rating of the load (light bulb), but the voltmeter measures 0V when it was completely discharges and as we turns on the power supply it climbs up to 12V and it climbs up higher and higher, but slower and slower over time. Does...
I suspect that at first the electrons on the other side of the plate in the capacitors are pushed to the light bulb that is the plate becomes more positive to compensate for the increase of electron on the other plate. Was this right? And can anyone refer me to a study or law regarding it?
I'd be glad if you were to include an example in resistors configuration with nodes on it. If it weren't much of a trouble. I cannot find a website that teaches network analysis with nodes embedded.
A node is a point wherein 3 or more wires constitutes it and the connection is in parallel. I don't know what point to look. But, if i were look at point d the 10 and 15 ohm resistors are connected in parallel. Sorry for the image.
Problem Statement: Finding the resistance when probed at point bc, cd and da
Relevant Equations: Series and Parallel resistance equation derived from kirchhoff's law with application of ohm's law
I genuinely don't know what to do on this one. The example our professor made isn't exactly clear...
I was just doing some review on my physics lecture and I stumble on the idea of what if there was an object hanging and the cord mass is also included in the weight and it's displaced upward without having velocity nor time hypothetically and the cord change mass. I tried solving it by W = fΔx...
I edited it now with 3 of the resistors we've used. The other group from our class did have the same result that the percent error increases along with the theoretical resistance. I do not know the details regarding the meter used. I redid it at home with different percent errors (different type...
I did and it was all on a breadboard(large). The resistors were enclosed on a glass casing with its terminal popping out. I redid the experiment at home and it seems like the culprit with mine is the length of the terminals, the percent error I've got is inconsistent, although it still seems...