If I move a 1kg body with an acceleration of 1 m/s^2 (F = ma = 1N) for 1 meter, I do 1J work.
If I move the same 1kg body the same 1 meter distance, but with acceleration 2 m/s^2 (F=2N), does that mean that I did 2 times more work (2J) than before?
Work W done by moving the object with force F for distance s is W = Fs.
When I move the same object the same distance but with twice the acceleration, does
the work done gets also doubled?
By F=ma, doubling the acceleration yields m*2*a = 2F -> 2Fs = 2W.
I've mostly read, that if I want to...
Hello!
If I pedal a bicycle, where is the force that moves the bike forward horizontally applied?
Is it the bottom of the back wheel or the center of the back wheel?
When the force applied to that point is F, does all that force goes into horizontal acceleration, or does some of that force go...
Hello!
The total force F = m*a applied to the bicycle is F = F1 - a*v^2,
where F1 is the initial force applied to the bicycle, a is a constant and v is the velocity.
That means that the total force applied to the bicycle decrease as velocity increases, like a wind resistance decreases...