Recent content by ME_student

I transfer next term as a junior. I would say Sophomore year was a lot of fun. I did pretty well in all my engineering classes.

Do you like math, phy, science, programming, circuits analysis, not having a life (social life), and studying all the time? If you like the following then I say go for it!

I think it's best for me to put this question here than to make a new thread. Apologies for threading jacking. I am a student who is about to enter junior year for mechanical engineering. Do we have any petroleum engineers here on physics forum? I was wondering what classes were like junior...

OP didn't know what a FBD was so I was going to start helping him/her by having him/her draw some FBD. BTW Mr. Chet if he used correct FBD's he wouldn't be here asking us questions. Obviously OP must have analyzed something wrong on his/her free body diagram.

Lets see some FBD's first.

This is how I think about it. Since we have T=1/2mv^2, T is nothing more than energy. Is energy a scalar or vector? It's a scalar, has no direction. So I believe energy doesn't have a direction so the negative sign will disappear. I used T instead of V since we use T a lot in dynamics.

Thanks Evo. I have taken everyones advice here. The recovery process has been good so far just staying busy with school and doing things to better myself. Like I said earlier glad I didn't ruin her marriage. I think the hardest part was recovering from the fact she blamed me for everything and...

Serious question here. I asked my ex very nicely if I could get a textbook I let her borrow because she was going to take the same class as well as the time we were dating. She blocked my number, she blocked me on facebook as well. She hasn't blocked me through email yet... She is mad at me...

Starting with block A Sum of the forces in x direction, right being plus (+) Equation 1: -T-mu_s*FN1-MU_s*FN2+W_A*sin (25)+Pcos (25)=0 Zero because the block is static. Sum of the forces in y direction, up being plus (+) Equation 2: FN1-FN2-W_A*cos (25)+P*cos (25)=0 Now looking at block...

How's that?

Not trying to be a smarty pants but that's why you rotate the image and zoom into identify the images and calculatuons. Let me try to rotate the images...

Okay I can do that... Next time. :smile:

Well I manage to figure out part A and part B of the question... Still let's discuss why my P force is wrong. Let me retake a few pics. Better?

Homework Statement I feel like I've spent way too much time on this problem... So the given information is on the image along with all my work. I am finding the acceleration of the block and the tension in the cable. I know R is going to be the same in all the cords because the pulleys are mass...

Sorry for the small iMage. I got it figured out.