Hi, I had those exercises and want to know if they're correct. Also, feedback/tips would be great from you, professionals.
$$A$$
1. Let's consider the oscillator with a friction parameter...
\begin{equation}
m \ddot{x}+\alpha \dot{x}=-\kappa x
\end{equation}
but with
\begin{equation}...
Hi, I'm trying to solve the problem from here: https://www.physics.uoguelph.ca/chapter-1-newtonian-mechanics
Exercise 1.1: Determine how the coordinates $$x$$ and $$y$$, as well as the basis vectors $$\hat{x}$$ and $$\hat{y}$$, change under a rotation around the $$z$$ axis by an angle $$α$$...
Hi, is it possible, is there any formula that can help me to take root from (for example) 1,2 without a calculator (by hand)?
For example, there is a cos(x) formula that can be calculated on the paper:
$$\cos x=\sum_{n=0}^{\infty}(-1)^{n} \frac{x^{2 n}}{(2 n) !}$$
There is the Babylonian method...
Hi, just wondering what this thing means.
$$
E^2_k|_{k=k_{res}}
$$
Just the k=k(res) after the vertical line. There is no definition in the textbook but in math does that mean from K=K(res) to something that can be dependent on a function or a situation?
Like definite integrals answer...
My bad
$$
\frac{24 \pi^3 \times 1.5^2 \times\left(10^{11}\right)^2}{\left(3 \times 10^7 \times 3 \times 10^8\right)^2 \times\left(1-0.0034^2\right)}=2×10^{-7}
$$
But there are no more dimensions.
meter²×sec²/(meter²×sec²)
Hi, I've just calculated the orbital precession for the earth using the sigma formula of general relativity.
$$
\sigma=\frac{24 \pi^{3} R^{2}}{T^{2} c^{2}\left(1-e^{2}\right)}=\frac{24\pi^3×1.5×10^{11}}{3×10^7×3×10^8(1-0.0034^2)}=0.012
$$
What is the unit of the result? Degrees per century or...
So, as I said the pressure difference is so minimal it is almost the perfect line trendline, of course. Also as some of you said, I've corrected the axis, applied the curve, and saw the result I was searching for.
Thank you, Messrs!
I did refitting the curve and found out that data has so few drops with fluctuations at the very small height it seems linear. Polynomial equations can solve anything but since the barometric formula is exponential, then it has also an exponential trend line. Everything looks fine now. I'll post...
Hey! Does anyone have the large/full description of Maxwell's demon thought experiment? I've read it on Wikipedia, but I was wondering if someone knows a better source I can reach legally.
Thanks.