My question is going to be rather specific. I am trying to understand how Gauss's law applies to this scenario. I know if a cylindrical shell is infinitely long, and there is an external electric field, the inside of the shell will have an electric field of zero everywhere. I am wondering...
I see. What if the ball was floating in a vacuum? Would it ever discharge? Can electrons jump within a vacuum or would that require an absurdly high amount of charge
If I have a metal electric conducting ball the size of an average snowball (Happy Holidays) and give it a charge of say 0.1 Coulombs and set it on a wooden table, will it ever discharge if not touched by anything else? If so, if it is wrapped in an electrical insulator, will it ever discharge...
Okay. So if I see a stationary proton and that proton begins to accelerate faster and faster in some direction, the B-field created will increase as it moves faster. Because the B-field changes, the E-field must change too. Will the transverse E-field of the proton increase or decrease?
Oops. I was looking at the link I referenced following the statement. I will put it below this message as well.
https://en.m.wikipedia.org/wiki/Current_density
Can you give me an example of a case where J is not related to v?
It does depend of J. That is correct. From what I'm looking at J depends on v. The equation being J = pv.
https://en.m.wikipedia.org/wiki/Current_density
When considering just two particles, I still see no way for the v in context of "vB" to be a different v than the one found in "J=pv"
I see that v is the velocity of the frame that you are transforming to relative to the frame that you are transforming from. My issue is with B. B is dependent on v as well. And I can't seem to see how these two v's would be anything but equal.
Okay, so I'm looking at the line that reads
E⊥′ = γ (E⊥ + vB)
In "vB" what is v?
B field created from moving point charge is proportionate to the v velocity of said point charge.
Are these both the same v?
Does that mean vB proportionate to v² ? Where v is the relative velocity of the...
The previous ones states that electric field and magnetic field change with respect to the frame. In this example I do not see how the electric field can be any different regardless of the chosen frame.
It does. It states "an atom or group of atoms that carries a positive or negative electric charge as a result of having lost or gained one or more electrons"