Sorry, I made a mistake in naming it. Although it really don't change the position of the methyl in the name I gave, since it's a cyclic structure, in both cases the methyl it's just a carbon away from the OH, but you're right I should have started counting towards the methyl group, so the name...
Sorry for not answering sooner. I've been a little busy, so I've been taking a deeper look at activating and deactivating groups. I believe the answer to the problem might be 3-methylphenol for compound 'A', and 2,4,6-tribromo-5-methylphenol for compound 'B'. Again, I'm thankful for the feedback
Your explanation led me to consider C6H5CH2OH (benzyl alcohol) as compound 'A,' which should have a slight acidic nature. Moreover, I recently learned that benzene derivatives capable of reacting with bromine water are those containing activating groups and it should generate...
I've figured out that both compounds have 4 unsaturations. The fact that they are insoluble in water makes me think they might have a benzene ring. When bromine water is added (I found out online that it's Br2 in water), perhaps some hydrogens from the benzene ring might be replaced. However...
I'm a teenager eager to learn more about math and physics. As a self-directed learner, I'm particularly interested in calculus and linear algebra. I'm thrilled to be part of this community and look forward to gaining knowledge and engaging in enriching discussions. Your expertise and insights...