Recent content by Tangeton

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    How Does the Inverse Square Law Apply to Calculating Distances Between Charges?

    I know I just said I have no eureka moments but... would this be the way to do ratios? 0.5F : 1/20^2 0.5 : 1/400 1: 1/200 1:1/10xSqrt of 2 1: 1/14.14 Although I don't know why it would be that you have to take the square root of 200...?
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    How Does the Inverse Square Law Apply to Calculating Distances Between Charges?

    I am in a panic but I would not be able to solve this question if I weren't in a panic anyway... My exam won't go down well anyway... I don't understand anything about the inverse square law or working with ratios in physics... I know I need 1F, and that it is somehow that d is 20x0.7 since...
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    How Does the Inverse Square Law Apply to Calculating Distances Between Charges?

    0.5F = k(Q1Q2/20^2) 200F = K(Q1Q2) What can I do from here..? Am I doing the right thing even? I see 3 unknowns here...
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    How Does the Inverse Square Law Apply to Calculating Distances Between Charges?

    I know the coulmob's law. I do not know Q1 or Q2 to solve it using coulomb is law. This is not helping. Please I need real help I just don't understand how to apply at all to these questions. I don't know if I am thick but I simply do not see it.. I have been crying over this question for over...
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    How Does the Inverse Square Law Apply to Calculating Distances Between Charges?

    I am faced with the following question: Two point charges X and Y, exert a force F on each other when they are at a distance d apart (x and y are opposite charges). When the distance between them is 20mm, the force exerted on each other is 0.5F. What is the distance d? I know that, e.g...
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    B Does having more neutrons in an isotope make it more or les stable?

    It's from a CGP book, quote ''In general, the greater the number of neutrons compared with the number of protons, the more unstable the nucleus.''
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    B Does having more neutrons in an isotope make it more or les stable?

    Does more neutrons in an isotope make it more or less stable? I got two contradicting sources. I am also quite confused overall about the whole isotope business. The definition of an isotope is that it is an atom with the same number of protons but different number of neutrons. For example...
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    Solving trigonometric equations using compound angle formula

    Ahh okay I forgot about that bit.. I guess I would have to remember to use the CAST diagram for my answer. Thanks for all help, everyone.
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    Solving trigonometric equations using compound angle formula

    4tan(θ)=3+3√3tan(θ) 3+3√3tan(θ)- 4tan(θ) = 0 3 + (3√3-4)tan(θ) = 0 (3√3-4)Tan(θ) = -3 Tan(θ) = -3/(3√3-4) θ = Tan^-1(-3/(3√3-4) ) = -68.3 (3sf) but the answer is 111.7... And upon plugging in x = -68.3 and x = 111.7, it turns out that they both do make the equation 2sinx = 3cos(x-60) equal on...
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    Solving trigonometric equations using compound angle formula

    Hello. I find this whole topic of compound angle formula really confusing. I've been doing equations like cos(60+x) = sinx using the co function identities so far, yet this one seems to be impossible to do using cofunction identities so I need to know how to do it using compound angle formula...
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    How is the UTS different from breaking stress and why?

    I understand the point you're trying to make about cross-sectional section remaining constant, but since Stress = F/A, if A is constant, should stress be still increasing with the force applied? I know that it is a stress vs strain graph, but strain is extension over length and the bigger the...
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    How is the UTS different from breaking stress and why?

    By definition the UTS is the maximum stress a material can take. But how exactly can a material not break after reaching the UTS if it is so? Why is there a breaking stress and how come on the graph of stress against strain the stress seems to decreases before the braking stress?
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    Speed of a satellite above the earth?

    Thank you for your answer. I get really worried when I see things like this in the marking scheme since it is hard to trust yourself over an exam paper. Thank you also for taking your time to do the question as one expression it was interesting to observe what it becomes since I ended up...
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    Speed of a satellite above the earth?

    (b) (i) A satellite of mass 2520 kg is at a height of 1.39 × 107m above the surface of the Earth. Calculate the gravitational force of the Earth attracting the satellite. Give your answer to an appropriate number of significant figures. Worked out to be F = 2.45 x 103 The satellite in part...
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