Recent content by Telis

Thank you, it is pretty clear for me now that at the surface/air interface will have ##\nabla \times \vec{P} \neq 0 ##. Then Griffiths continues and says that "if the problem exhibits spherical, cylindrical, or plane symmetry then evidently in such cases ##\nabla \times \vec{P} = 0 ##." So...

In Griffith's "Introduction to Electrodynamics" says that in a bar electret the curl of the polarization does not equal zero everywhere. Why is that ? Thanks in advance