Okay, so we did a lab in class with Na2CO3 in BaCl2 first. The reaction formed a white precipitate, and I suppose the products are BaCO3 + 2NaCl. Not sure if NaCl is dissolved or not, or if it was the white precipitate I saw, but anyways, here's my question...
We added HNO3 to that new...
Can you work units cubed the same way you can work units that aren't cubed in dimensional analysis?
Like...does 1m3 equal 250cm3 like it would if they weren't cubed?
For example: If they gave you KClO and asked you to name it...
The answer is Potassium Hypochlorite, because you base it off of the loss of two oxygen atoms from the most common chlorine ion (ClO3). My question is, why can't I base it off of Clorite (ClO2), so that the name of KClO would then...
So how do you know when a chemical is an acid or not? I know that an acid is a compound that, when dissolved, yields H atoms, but does that mean than any compound with H in it is (or has the potential to be) an acid?
For example:
HNO2, I put down that it was Hydrogen Nitrite, but the...
@Mark - Oh! No, I knew that most of you would know the basic identities, I was just questioning the methods that they used to get started.
I've gone through it again, and I'm still coming up short.
"Re-write as
1-cos^2 x + cot^2 x - cos^2 x cot^2 x = sin^2 x + cot^2 x (1 - cos^2 x) =...
@WannabeNewton = Cot2x is Cosx2/Sinx2
I'm just confused how you guys knew that stuff right off the bat. The way that I worked up to this point was simply eliminating anything to do with tangent and going from there. How do you guys know that you're supposed to work with csc and sin as you...
Homework Statement
(cos4x) + 2(cos2x)(sin2x) + (sin4x)
Homework Equations
All Pythagorean, reciprocal, and quotient identities.
The Attempt at a Solution
Okay, so I thought that maybe (cos4x) + (sin4x) might be the same as its Pythagorean identity (which would make that mess just...
Homework Statement
Simplify: 1 + (cot2x) - (cos2x) - (cos2x)(cot2x)
Homework Equations
All reciprocal, quotient, and Pythagorean identities.
The Attempt at a Solution
I have spent SO much time trying to figure this out, the answer is "1" but I cannot get it! I managed to get "1 +...
I don't think I have enough information to plug into its equation though. If it gives me the wavelength, could I use that to solve for the amplitude? (Considering this is a spring, and not a wave?)
Ah! I figured it out! PE is the same as KE when KE is maxxed. :D I found the answer, w00t! Thanks so much for helping me!
Now, there's still the issue of Amplitude; which plays another role in one of my other practice problems. All I really know and all I can gather is that amplitude relates...