Recent content by whdahl

Yes. After reading through that wiki page and another on dynamic programming, it seems that this is a problem that can be solved using VBA in excel.

Another constraint would be that x > y > z > w >= 0 because it is best to have the highest amount of smaller chips. Is there an efficient way, using matrices perhaps, of solving for solutions?

Hey everyone. I was pondering how best to optimize a chip arrangement for a poker game. This is the scenario I've thought up: There are 4 denominations of colored chips with a set value. White (W) = 0.05 Red (R) = 0.25 Blue (B) = 1.00 Green (G) = 5.00 A player wants to purchase 40 dollars...

Because R2 = 5 Ohms, not 10 Ohms

I am just curious as to where the 4.9 came from?

Literally the moment I sent that, I found my mistake. I did not carry the \frac{mgsin10}{cos10} over correctly.

I don't see where my mistake is, but I've ended up with an extra cos(10) in the final answer.

I know how to solve simultaneous equations, but I am not getting the solution they show in this case. Solving one of the equations for Fn or N and substituting that in the second equation will allow you to eliminate one of the variables. However I am not getting the solutions they provide, I am...

This is what the second part of your problem should look like so far.

Remember, if the arrow is flying at an angle \theta its horizontal velocity will be 23.1cos(\theta) Use this to solve for the time it will take the arrow to travel the distance of 38 meters. It should end up being t = \frac{38}{23.1cos(\theta)} Hopefully this will push you in the right direction.

Homework Statement The problem statement is in the attachments.Homework Equations F=maThe Attempt at a Solution I uploaded the solution to the problem. I have had no trouble deriving the first two equations for the summation of forces in the x, n and t directions, however I am having trouble...

You need to find the net force acting on the box which is the force the man is applying minus the friction force (Which always opposes motion). The formula for frictional force is F = μkN where μk is the stated coefficient of friction and N is the weight of the box in Newtons. Now that you have...

The kinetic energy from the box is then stored as spring potential energy P=1/2kx^2. I think I see my problem. I have the final equation: 126J=126Nm=1/2(50N/cm)x^2 25200Ncm=50(N/cm)x^2 x^2=504cm x=22.45cm Thank you guys, you helped a lot!

It is a work problem

Homework Statement A 7.0kg box moving at 6.0m/s on a horizontal, frictionless surface runs into a light spring of force constant 50N/cm . What is the maximum compression of the spring? Homework Equations K=1/2mv^2 The Attempt at a Solution K=1/2(7.0)(6)^2 = 126N 126N/(50N/cm)...