Help please, I seem to have reached an impasse

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A stone is thrown horizontally from a 50.0 m high cliff at a speed of 18.0 m/s. To determine the speed and angle of impact, the stone's vertical and horizontal motions must be analyzed separately. The time taken to fall 50.0 m can be calculated using the formula for free fall, leading to a vertical velocity at impact. The horizontal velocity remains constant at 18.0 m/s. Ultimately, the stone impacts the beach with a specific speed and angle derived from these calculations.
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I am not having any luck with the following question. Please help...

A stone is thrown horizontally over the edge of a cliff with a speed of 18.0 m/s. The cliff is 50.0 m above a flat beach. With what speed and angle of impact does the stone land?
 
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I got it, never mind.
 
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