How Long Would It Take to Try Every Combination on a 0-59 Dial Lock?

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Discussion Overview

The discussion revolves around calculating the time required to try every possible combination on a dial lock numbered from 0 to 59, considering variations in the number of digits in the combination (three or four) and the direction of turning the dial. Participants explore different interpretations and assumptions related to the problem.

Discussion Character

  • Exploratory
  • Mathematical reasoning
  • Debate/contested

Main Points Raised

  • One participant calculates the total number of combinations for both three and four-digit combinations, arriving at 13,176,000 possibilities and estimating the time to try them all.
  • Another participant questions whether the direction of turning the dial should be considered, suggesting that it could double the number of combinations.
  • A different participant notes that the type of lock could affect the calculations, mentioning that some locks may allow for a range of numbers to be accepted, which complicates the problem.
  • One participant expresses uncertainty about the validity of combinations that include repeated numbers or specific sequences.
  • Another participant proposes a different approach to the problem, suggesting a method based on probabilities related to correct and incorrect answers, leading to a vastly different time estimate.

Areas of Agreement / Disagreement

Participants do not reach a consensus on the assumptions necessary for solving the problem, particularly regarding the type of lock, the direction of turning the dial, and the validity of certain combinations. Multiple competing views remain throughout the discussion.

Contextual Notes

Limitations include unclear definitions of the lock type, assumptions about the direction of turns, and the acceptance of specific combinations. These factors contribute to the uncertainty in the calculations presented.

gohydj2003
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Help me solve this maths riddle!

John forgot to bring his house keys with him,so he must use secret numbers to open his house door.But he reasiled that he totally forgot the numbers,despite of that,he still insisted using the secret numbers. When he got there, he came to a combination lock on the door, with the dial numbers going from 0 to 59. Unfortunately, he forgot whether there were three or four numbers in the combination, or even which direction to turn the wheel!



If it takes him 15 seconds to try a single combination, how many days will it take him to to try every possible combination? Please round to the nearest day.


please help..i rephrase it a little...help please..i need the solution ASAP..as i need to pass up by tomorrow!
 
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From 0 to 59, that are 60 possibilities, I assume? (is that including or excluding 0 and/or 59?)
60^3 possibilities with 3 numbers.
60^4 possibilities with 4 numbers.
60^3+60^4=13176000 possibilities
13176000*15=197640000 seconds=3294000 minutes=54900 hours=2287.5 days.
 
I just saw exactly the same question on "math message board" except that it was phrased in terms of a bank robber trying to open a vault!
 
Should you multiply that answer by 2 because he doesn't know what direction to start turning and there's 2 possiblities there as well?
 
They should have told you exactly what type of lock this was. I assume koroljov's approach is correct for a type of lock that you would find on a http://www.hevanet.com/gillesp/briefcase-lock.JPG a student would put on their locker at school, which changes things. In that case, you would definitely have to mutiply both the number of combinations of a 3 number combination and a 4 number combination by 2 (for going to the right and then to left) and then add them, etc. But... that assumes for each combination that your dialing in a number, turning left, dialing in another, turning left, etc., and my experiences have always been dialing in a number and then turning the opposite direction of the previous turn, which would change the answer. I would also want to know whether or not to assume that combinations like 0-0-0, 1-1-1-1, 0-1-0 are valid entries.
 
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lol... gech. With your picture links, there's no guessing what it is you're talking about. Since direction was a concern, I imagined that they were talking about the high school locker kind of lock. But house locks are usually of the briefcase style. Assuming they're talking about a padlock, I remember on my high school locker lock that you didn't have to get it quite exact anyway. If your combination were 37-24-12 and you did 38-23-11, it would usually open. The numbers on the dial were a more accurate scale than the mechanics of the lock required. That changes the problem a bit too. So the real answer is "Unknown--not enough information given. Need to know the tolarance of the lock". Dohydj, teachers usually don't like these kind of answers.
 
try this

i assume i solve it unless their is misunderstanding to the given
(2 * 60)^4 * 15 / 3600 / 24 =36000 days =98.6 years

(as two right or wrong questions has two probabilities and they are two they have four combinations
3 right or wrong questions are 2^3 and so on......)
so one can solve number of possible combinations of 500 right or wrong questions is 10^(500log2) as 2^500 gives math error on calculator
 
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