Why does glucose have a lower rf value than fructose?

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Fructose and glucose, while having the same molecular formula and being isomers, exhibit different behaviors in thin-layer chromatography (TLC) due to their structural differences. The varying positions of functional groups in these molecules lead to different interactions with the stationary phase during chromatography. This difference in molecular structure significantly influences how each sugar interacts with the stationary phase, resulting in fructose appearing higher on the TLC plate than glucose. The efficiency of chromatography as a separation method is largely attributed to these nuanced interactions between the molecules and the stationary phase.
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Even though their molecular formulas are the same? Fructose is an isomer of glucose and they are both cyclic and have 5 carbons so I was wondering why fructose was higher on the TLC plate than glucose.
Thank you.
 
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It is not about molecular formulas, it is about interactions between the molecule and the stationary phase. These interactions are extremely sensitive to the molecule structure, which is why chromatography is so efficient as a separation method.
 

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