My Attempt At Re-entry Temp. Calculation
I wanted to figure out the temperature(t2) of any object based on things such as its specific heat capacity, re-entry speed, etc.
Work: W = Fy
Force by Air: FD = 1/2pv2CDA
Energy-temperature relationship: Q = mc(t2 - t1)
Setting things equal & solving for t2 gives:
t2 = (1/2pv2CDAy+mct1) / mc
(I'm sorry I could not get latex to format all of the formulas correctly so I formatted none of them...)
So, how accurate is this equation in describing temperature gain through freefall back down to earth?
Re: My Attempt At Re-entry Temp. Calculation
I'm going to take a guess and say you get an estimate by finding the dynamic pressure (q = 0.5 * density * velocity^2) and solving for the adiabatic heating due to the pressure rise. This doesn't take any skin friction into account however.
|All times are GMT -5. The time now is 07:37 AM.|
Powered by vBulletin Copyright ©2000 - 2014, Jelsoft Enterprises Ltd.
© 2014 Physics Forums