Proof of Exponential Interarrival times times

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The discussion focuses on proving that exponential interarrival times always result in a Poisson process, which is the reverse of the common proof that establishes the relationship between Poisson processes and exponential interarrival times. The fundamental assumption of the Poisson distribution is that the probability of a single arrival in a small time interval is constant, while the probability of multiple arrivals is negligible. The proof typically involves differential equations and can also be approached using Taylor series expansion to demonstrate that only one arrival can occur in a given interval. The participant suggests that the waiting time for the second arrival follows a Gamma distribution, and integrating this distribution leads to the Poisson distribution, although the integration process is complex. This exploration highlights the mathematical connections between these statistical concepts.
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The proof that poisson process has exponential interarrival time is common place. The proof which i am trying to do is that, exponential interarrival times will always be poisson process, its like the reverse of the earlier proof. Could you help me with that.
 
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The fundamental assumption of the Poisson distribution is that, for some very small time interval, the probability of a single arrival is a constant and the probability of more than one arrival in that time interval is so small it can be ignored. The proof that that hypothesis leads to the Poisson distribution is given in any good probability text that discusses the Poison distribution. You can also treat that as a differential equations problem (the rate of change of total arrivals is constant) that has an exponential function as solution.
 
I am not sure if I truly follow you. The proof that you can only have one arrival in one interval and the probability of getting two arrival is zero, is done through taylor series expansion. But how does it show that the exponenttial interarrival shall always satisfy the poisson properties.

What I tried is the total time, or waiting time let's say for the second arrival is Gamma Distribution. So if we integrate the gamma distribution it shall give us a poisson distribution. However the integration is winding, but it does yield the poisson distribution at the end.
 

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