Any one help. Adjugate of 2X2 matrix

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To find the adjugate of a 2x2 matrix, switch the positions of the elements in the main diagonal and change the signs of the off-diagonal elements. For a matrix A = (a b; c d), the adjugate is given by adj(A) = (d -b; -c a). This method is a simplified version compared to finding the adjugate of a 3x3 matrix, which involves calculating cofactors and taking the transpose. The discussion confirms that the adjugate can be easily remembered with this straightforward approach. Understanding this process is essential for further calculations involving the inverse of matrices.
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I know how to find the adjugate of 3x3 matrix. from the defination.

How to find adjugate of 2x2 matrix.

e.g A= ( 1 3 )
______( 2 4 )

adjoint .

I know how to find adjugate and inverse. of 3 * 3 matrix

First . I find matrix of cofactor. from the defination. (n-1)(n-1) matrix * (sign associated with the element's position).

Second, we taking the transpose we get the adj(A)

Then we find the det(A).

Finally, A^-1 = 1/det(A) * adj(A)The inverse of A.

AA^- = A^-A=I and A adj(A) = det(A)I

The inverse of A = det(A)I/ A^-
 
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Isn't \text{adj}\left(\begin{array}{cc}a&b\\c&d\end{array}\right)=\left(\begin{array}{cc}d&-b\\-c&a\end{array}\right)?
 
cristo said:
Isn't \text{adj}\left(\begin{array}{cc}a&b\\c&d\end{array}\right)=\left(\begin{array}{cc}d&-b\\-c&a\end{array}\right)?

Just remember it? right?
 
Charles007 said:
Just remember it? right?

yes, that is it for a 2x2 matrix, switch elements 1 and 4; change the sign of elements 2 and 3
 
rock.freak667 said:
yes, that is it for a 2x2 matrix, switch elements 1 and 4; change the sign of elements 2 and 3

OK. thx. :smile:
 
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