Probability: Independent vs. Dependent events

trojansc82
Messages
57
Reaction score
0

Homework Statement



2. Let a random experiment be the cast one “six-sided” die and one “four-sided” die.

(a) Give an example of two independent events and justify your answer.
(b) Give an example of two dependent events from this sample space and justify your answer.

Homework Equations



Independent event:
P(A ∩ B) = P(A) * P(B|A) = P(A) * P(B)

Dependent event:

Not Independent, i.e. P(A) * P(B) = P(A ∩ B)


The Attempt at a Solution



A = {(1,1), (1,2)}

B = {(1,1), (2,1)}

P(B) = P(B|A) = P(A ∩ B)/P(A) = (1/24)/(2/24) = 1/2

P(B) is not equal to 1/2
 
Physics news on Phys.org
trojansc82 said:

Homework Statement



2. Let a random experiment be the cast one “six-sided” die and one “four-sided” die.

(a) Give an example of two independent events and justify your answer.
(b) Give an example of two dependent events from this sample space and justify your answer.

Homework Equations



Independent event:
P(A ∩ B) = P(A) * P(B|A) = P(A) * P(B)

Dependent event:

Not Independent, i.e. P(A) * P(B) = P(A ∩ B)


The Attempt at a Solution



A = {(1,1), (1,2)}

B = {(1,1), (2,1)}

P(B) = P(B|A) = P(A ∩ B)/P(A) = (1/24)/(2/24) = 1/2

P(B) is not equal to 1/2

No one has replied, possibly because your work is so terse, making it difficult to understand.

Are A and B the two events? What do they represent (in words)?

On one line you say that P(B) = 1/2, and on the next line you say that P(B) is not equal to 1/2. How can a given probability be equal to and also not equal to the same number?
 
Prove $$\int\limits_0^{\sqrt2/4}\frac{1}{\sqrt{x-x^2}}\arcsin\sqrt{\frac{(x-1)\left(x-1+x\sqrt{9-16x}\right)}{1-2x}} \, \mathrm dx = \frac{\pi^2}{8}.$$ Let $$I = \int\limits_0^{\sqrt 2 / 4}\frac{1}{\sqrt{x-x^2}}\arcsin\sqrt{\frac{(x-1)\left(x-1+x\sqrt{9-16x}\right)}{1-2x}} \, \mathrm dx. \tag{1}$$ The representation integral of ##\arcsin## is $$\arcsin u = \int\limits_{0}^{1} \frac{\mathrm dt}{\sqrt{1-t^2}}, \qquad 0 \leqslant u \leqslant 1.$$ Plugging identity above into ##(1)## with ##u...
Back
Top