View Single Post
cragwolf is offline
Mar5-12, 04:31 PM
P: 210
Why does the fact that the combined energy of 8Be and 4He is (almost) the same as the energy of an excited state of 12C greatly increase the probability of that reaction (i.e. 8Be + 4He → 12C + stuff) occurring? Apparently it doesn't have to be exactly the same, but does it make any difference if it's slightly less vs slightly more?
Phys.Org News Partner Physics news on
Physicists design quantum switches which can be activated by single photons
'Dressed' laser aimed at clouds may be key to inducing rain, lightning
Higher-order nonlinear optical processes observed using the SACLA X-ray free-electron laser