Photo-electric effect, Compton Scattering

AI Thread Summary
The discussion centers on calculating the maximum kinetic energy of electrons ejected from copper foil due to Compton scattering by a 17.5 KeV x-ray beam. The initial reasoning incorrectly assumed that the energy loss from the x-ray's wavelength change could be directly equated to the energy gained by the electron. Instead, the correct approach involves calculating the original x-ray wavelength, applying the change in wavelength, and then determining the energy difference between the two states. This method yields a maximum kinetic energy of 1.1 KeV for the electrons, clarifying the misunderstanding in the initial calculation. Understanding the relationship between energy and wavelength is crucial for accurate results in this scenario.
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Homework Statement


What is the maximum kinetic energy of electrons knocked out of a thin copper foil by Compston scattering of an incident beam of 17.5 KeV rays? Assume the work function is negligible.


Homework Equations


Δλ = h/mc (1-cosθ)


The Attempt at a Solution



I reasoned that the greatest energy transfer to an electron will occur when the x-ray rebounds at 180 degrees, in which case the change in wavelength is 4.85 x 10^-12 m.

I figured that the wavelength of the x-rays increases by this amount, thereby decreasing in energy. I thought I could therefore take this change in wavelength and calculate the energy associated with it using E = hc/Δλ, and I got E = 256 KeV.

However, the answer key requires that you calculate the wavelength of the original x-ray, add Δλ, then calculate the energy and deduct the original energy. It yields a different answer, 1.1 KeV.

I don't understand why you can't say that the energy loss associated with the increase in the wavelength of the x-ray is completely transferred to the electron and then be done with it. What am I missing? Thanks!
 
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Does anybody have any insight into what I'm doing wrong here? I'd appreciate any and all help :).
 
mm2424 said:

The Attempt at a Solution



I reasoned that the greatest energy transfer to an electron will occur when the x-ray rebounds at 180 degrees, in which case the change in wavelength is 4.85 x 10^-12 m.

I figured that the wavelength of the x-rays increases by this amount, thereby decreasing in energy.
So far, so good.
I thought I could therefore take this change in wavelength and calculate the energy associated with it using E = hc/Δλ, and I got E = 256 KeV.
Not quite. First, note that it's impossible for a 17.5 keV photon to lose 256 keV of energy.

You have two energies, E1 = hc/λ1 and E2 = hc/λ2.

The energy difference E1-E2 is the difference between the hc/λ terms, not hc/Δλ. What you did is equivalent to saying
(1/5) - (1/3) = 1/(5-3) = 1/2,​
which is not true.

Can you take it from here?

However, the answer key requires that you calculate the wavelength of the original x-ray, add Δλ, then calculate the energy and deduct the original energy. It yields a different answer, 1.1 KeV.
Yes, that is the basic idea.
 
Thanks, that makes sense!
 
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