Electric Field Distribution of a disk

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To find the electric field at point P, which is 10 cm above the center of a thin disc with a central hole, the total charge of 10^-3C needs to be uniformly distributed over the surface. The surface charge density (σ) can be calculated by determining the total surface area of the disc, excluding the area of the hole. The differential charge element (dq) can indeed be set up as dq = σ2∏rdr, utilizing the symmetry of the configuration. Additionally, the acceleration of an electron at point P can be calculated using the electric field value obtained. This approach effectively combines charge distribution and electric field calculations in a uniform manner.
davidflip
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Hi can someone help me with this problem?

A thin disc of radius 60 cm has a hole its center of radius 30 cm. A total charge of
10^-3C is distributed uniformly on its surface. Find E at a point P which is 10 cm. on the central axis of this disc.
What would be the acceleration of an electron passing through point P ?. Mass of electron = 9.11*10^-31 Kg.

How would I set up dq for this?
would it simply be dq= σ2∏rdr? and if it is what is the numerical value for σ?

Thank you!
 
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You have a uniform charge distribution. Can you calculate the total surface area of your disk? This should give you σ.

would it simply be dq= σ2∏rdr?
If you use the symmetry of the setup, you can use that.
 
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