Where does the O-O-H come from in this hydroboration-oxidation mechanism?

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The discussion centers on confusion regarding the source of the O-O-H group in a chemical reaction mechanism. The user notes that H2O is introduced only in the final step, while H2O2 is already utilized, leading to uncertainty about where the additional oxygen originates. They initially suggest that the oxygen must come from NaOH dissociating into Na+ and OH-, but this raises concerns about electron balance. The conversation reveals a misunderstanding about the representation of reactants in the reaction arrow, clarifying that it indicates what is being used rather than the total quantities involved. The user acknowledges this point, indicating a deeper understanding of the reaction dynamics.
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I cannot for the life of me figure out where the O-O-H comes from that got added in the
3rd step! :confused:

Here's image of the reaction mechanism:

boricacid.jpg


The H2O is not used until the last step and the H2O2 has already been used (except for the H+), so the other O that adds to the OH- to form O-O-H must be coming from the NaOH when it dissociates into Na+ and OH-...
But this would not make sense because we would have an OH- and an O- adding together, and that would be too many electrons! :confused:

Thank you so much! :)
 
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There is more of H2O2 from where it came from.
 
Oh! Okay! I thought that there could only be one molecule of H2O and H2O2 and NaOH because that is what is shown on the reaction arrow.
But, I guess, that only shows what is being used...not the quantities of each...

Thank you! :)
 
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