What is the difference in applying -ve voltage at emitter and +ve coll

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The discussion centers on the impact of applying negative voltage at the emitter versus positive voltage at the collector in transistor circuits. It highlights that the power supply voltages influence the necessary input voltages, with specific examples showing how different negative supply levels affect transistor operation. The first circuit operates as a basic Emitter-Coupled Logic (ECL) unit, with defined input voltage ranges for logic states. The second circuit, while functionally similar, does not support the same input/output voltages as the first. Understanding these differences is crucial for designing effective transistor circuits.
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What is the difference in applying -ve voltage at emitter and +ve voltage at collector in attached circuit image? Really what I think is both circuits in thae image are identical. But then why -VEE?

-Devanand T
 

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The power supply voltages also affect the necessary input voltages.

For example in the second diagram, the transistor with -1.3 volts on its base will be turned off if the negative supply line is grounded but it is conducting if this line is at -5.2 volts.

This is because the base is more positive than the negative supply line in the second case, but less positive in the first case.
 


dexterdev said:
What is the difference in applying -ve voltage at emitter and +ve voltage at collector in attached circuit image? Really what I think is both circuits in thae image are identical. But then why -VEE?

-Devanand T
Over what range of input voltages will the arrangement in (a) function as an amplifier?

What about (b)?
 


the circuit in (a) is basic ECL unit, range of inputs is 2 logic states at input -1.7 V and -0.8 V.

I was asking that what difference (a) has with (b) in voltage supply applied in terms of polarity.
 
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dexterdev said:
the circuit in (a) is basic ECL unit, range of inputs is 2 logic states at input -1.7 V and -0.8 V.

I was asking that what difference (a) has with (b) in voltage supply applied in terms of polarity.
(b) will function in the same manner, but not with the input/output voltages that cause (a) to work.
 
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