What would E field addition be if Gauss's law was different

Curl

What if Gauss' Law was
div(E)=q²/eps₀

Then if we had two point charges, how could we calculate the resultant E field at an arbitrarily point? Obviously superposition would not work anymore, so how could it be done mathematically?

This is essentially a math question

Curl	What would E field addition be if Gauss's law was different Tweet What if Gauss' Law was div(E)=q²/eps₀ Then if we had two point charges, how could we calculate the resultant E field at an arbitrarily point? Obviously superposition would not work anymore, so how could it be done mathematically? This is essentially a math question