Calculating Work on a Sliding Block on an Inclined Plane

AI Thread Summary
A block on a frictionless inclined plane is pulled up at constant speed by a force F, and the discussion focuses on calculating the total work done on the block and the work done by gravity. The total work Wtot is the sum of the work done by the applied force and the work done against gravity. Participants express confusion over the correct formulation of the work done by gravity, with some incorrectly applying factors in their calculations. The work done by gravity is identified as negative due to the direction of the gravitational force relative to the displacement. Clarifications are made regarding the correct input values for calculations, emphasizing the importance of accuracy in the equations used.
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Homework Statement


A block of weight w sits on a frictionless inclined plane, which makes an angle (theta) with respect to the horizontal. A force of magnitude F, applied parallel to the incline, pulls the block up the plane at constant speed.

1)The block moves a distance up the incline. The block does not stop after moving this distance but continues to move with constant speed. What is the total work Wtot done on the block by all forces? (Include only the work done after the block has started moving, not the work needed to start the block moving from rest.)

2)What is Wg, the work done on the block by the force of gravity as the block moves a distance up the incline?

Homework Equations



Wtot = the sum of all work factors right ? So I have to find the work from the force going up the ramp, the work from gravity. ??


The Attempt at a Solution



I think the answer to q1 is W-tot = FL + (-wsin(theta))+N (The opposite force of mg = w)

But this is not correct but I don't know why?

Anyone?
 
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For the total work, what does the work energy theorem say?

for work done by gravity, use work = \vec{F}\cdot\vec{d}
 
love how i got Wgravity wrong...


Wf= -mgcos(theta) * L

(from masteringphysics, your answer is off by a multiplactive factor..)
 
guslergusler said:
love how i got Wgravity wrong...


Wf= -mgcos(theta) * L

(from masteringphysics, your answer is off by a multiplactive factor..)

Wf is work by the force F?

Wf = mgsin(theta)*L

F must be mgsin(theta) acting up the plane.
 
sorry i meant force done by gravity
 
guslergusler said:
sorry i meant force done by gravity

work done by gravity is -mgsin(theta)*L
 
that's exactly what i put...

but masteringphysics says I'm off by a multiplactive factor,,
 
guslergusler said:
that's exactly what i put...

but masteringphysics says I'm off by a multiplactive factor,,

hmmm... did you put in -wsin(theta)*L exactly?
 
thank you

my fault ... i input -wgsin(theta)*L
 
  • #10
guslergusler said:
thank you

my fault ... i input -wgsin(theta)*L

no prob.
 
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