Write an exponential equation from this data (data table included)

AI Thread Summary
To create an exponential equation from the provided population data, the general formula y = a(b)^x is used, where 'a' and 'b' are constants. The user is advised to select two data points, preferably from the endpoints (1954 and 1994), to establish two equations: 132459 = ab^1954 and 514013 = ab^1994. Dividing these equations will eliminate 'a' and allow for the calculation of 'b'. It is also suggested that a least squares fit might be a suitable method for modeling the data. Understanding these steps is crucial for deriving the exponential model accurately.
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Homework Statement


- The following table gives the population of a city over time:
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Homework Equations



I know this equation: y = a(b)x

and exponential growth: b = 1 + growth rate and b = 1 - decay rate

The Attempt at a Solution



I know from back in chapter 2 that first differences = linear model, second differences are the same = quadratic and if the 3rd differences are the same then its a cubic model...but that doesn't work here. I am completely stuck...how do I find the model. Any hints/tips/methods will be greatly appreciated! Thanks!
 
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There are two unknown constants in your formula, a and b. You need two equations to solve for two unknowns so pick two points (typically, it is best to endpoints, here 1954 and 1994).

That will give you 132459= ab^{1954} and 514013= ab^{1994}

It should be easy to see that dividing one equation by the other will eliminate a, leaving a single equation to solve for b.
 
Perhaps you are supposed to find a best least squares fit to the data?
 
I tried to combine those 2 formulas but it didn't work. I tried using another case where there are 2 red balls and 2 blue balls only so when combining the formula I got ##\frac{(4-1)!}{2!2!}=\frac{3}{2}## which does not make sense. Is there any formula to calculate cyclic permutation of identical objects or I have to do it by listing all the possibilities? Thanks
Since ##px^9+q## is the factor, then ##x^9=\frac{-q}{p}## will be one of the roots. Let ##f(x)=27x^{18}+bx^9+70##, then: $$27\left(\frac{-q}{p}\right)^2+b\left(\frac{-q}{p}\right)+70=0$$ $$b=27 \frac{q}{p}+70 \frac{p}{q}$$ $$b=\frac{27q^2+70p^2}{pq}$$ From this expression, it looks like there is no greatest value of ##b## because increasing the value of ##p## and ##q## will also increase the value of ##b##. How to find the greatest value of ##b##? Thanks
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