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Multilinear Maps 
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#1
Oct911, 12:46 PM

P: 532

Here is a bilinear map φ of two vector spaces V₁ & V₂ into another vector space N with
respect to the bases B = {e₁,e₂} & B' = {e₁',e₂'}: φ : V₁ × V₂ → N  (m₁,m₂) ↦ φ(m₁,m₂) = φ(∑ᵢλᵢeᵢ,∑_{j}μ_{j}e'_{j}) _______________________________= φ(λ₁e₁ + λ₂e₂,μ₁e₁' + μ₂e₂') = φ(λ₁e₁ + λ₂e₂,μ₁e₁') + φ(λ₁e₁ + λe₂,μ₂e₂') _______________________________= φ(λ₁e₁,μ₁e₁') + φ(λ₂e₂,μ₁e₁') + φ(λ₁e₁,μ₂e₂') + φ(λe₂,μ₂e₂') _______________________________= λ₁μ₁φ(e₁,e₁') + λ₂μ₁φ(e₂,e₁') + λ₁μ₂φ(e₁,e₂') + λ₂μ₂φ(e₂,e₂') _______________________________= ∑ᵢ∑_{j}λᵢμ_{j}φ(eᵢ,e_{j}') (Hope that's right!) Now in a discussion of bilinear (quadratic, hermitian) forms the terms φ(eᵢ,e_{j}') in ∑ᵢ∑_{j}λᵢμ_{j}φ(eᵢ,e_{j}') are elements of a field, & there seems to be quite a lot of theory built up for the special case of N being a field, but thus far I can't really find any discussion of what happens when the φ(eᵢ,e_{j}') elements are elements of a general vector space. Furthermore, the general case of multilinear (nlinear) maps expressed in this way seem to follow the same pattern of focusing on fields (or rings), e.g. determinants. The limited discussions of tensors & exterior algebra I've seen also follow this format of focusing on maps into a field. Just wondering what there is on maps of the form φ : V₁ × V₂ × ... × V_{n}→ N φ : V₁ × V₂ × ... × V_{n}→ V₁ × V₂ × ... × V_{n} φ : V₁ × V₂ × ... × V_{n}→ W₁ × W₂ × ... × W_{n} φ : V₁ × V₂ × ... × V_{n}→ W₁ × W₂ × ... × W_{m} (all being vector spaces) as in what kind of books there are discussing this, what this would be useful for etc... 


#2
Oct911, 06:26 PM

Sci Advisor
P: 906

i believe that what you are looking for is "the tensor product" which is "the most general bilinear map" (with two vector spaces) or "multilinear map" (with more than two).



#3
Oct1011, 06:33 AM

P: 532

Thanks for the response, so I take it that φ : V₁ × V₂ → N is the "most general bilinear map"
that can be formed because of the "universal property" [that φ is the most general bilinear map because for any other bilinear map h : V₁ × V₂ → M you have a unique linear map ω : N → M such that h = ω o φ] which if I understand it correctly says that: ω o φ : V₁ × V₂ → M  (m₁,m₂) ↦ (ω o φ)(m₁,m₂) = ω[φ(∑ᵢλᵢeᵢ,∑_{j}μ_{j}e'_{j})] __________________________ = ω[λ₁μ₁φ(e₁,e₁') + λ₂μ₁φ(e₂,e₁') + λ₁μ₂φ(e₁,e₂') + λ₂μ₂φ(e₂,e₂')] __________________________ = ω[λ₁μ₁φ(e₁,e₁')] + ω[λ₂μ₁φ(e₂,e₁')] + ω[λ₁μ₂φ(e₁,e₂')] + ω[λ₂μ₂φ(e₂,e₂')] __________________________ = λ₁μ₁ω[φ(e₁,e₁')] + λ₂μ₁ω[φ(e₂,e₁')] + λ₁μ₂ω[φ(e₁,e₂')] + λ₂μ₂ω[φ(e₂,e₂')] __________________________ = ∑ᵢ∑_{j}λᵢμ_{j}ω[φ(eᵢ,e_{j}')] is linear, which itself is just a fancy way of ensuring that image elements of φ are linear because they can be mapped to image elements of a separate bilinear map h. So I take it that when you generalize this to an indexed product of vector spaces the tensor product that results is also the the most general multilinear map φ : ΠᵢVᵢ→ N? 


#4
Oct1011, 12:23 PM

Sci Advisor
P: 1,716

Multilinear Maps
Linearity makes sense when vector space is replaced by Rmodule where R is a commutative ring. 


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