Question for geometers: How to describe this problems of this kind?by Galileo Tags: geometric phase, holonomy, nonholonomic system 

#1
Feb1112, 04:30 AM

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Consider the (physics) situation of a sphere of radius R rolling without slipping on a plane. The configuration of the sphere is given by the cooordinates of the center of the sphere and two angles for its orientation. When the sphere rolls over some given (closed) path in the plane, then its orientation can be changed relative to the starting orientation.
What would be the way to describe the kinematics of this system or systems like this? I would like for example  to derive formulas for the final orientation given the starting orientation and a closed path on the plane.  Answer whether any orientation can be achieved at the origin by some path starting from a given orientation at the origin (i suspect yes).  understand the general framework for decribing such systems and the major theorems known as this is heavily connected to geometric phases in physics. I think mathematics calls it a holonomy, but physicists call it a nonholonomic system (go figure) Most of what I googled on holonomy was completely incomprehensible to me and I couldn't find any connection with the described physical situation. If anyone can explain (give short overview of) this matharea to a physicist and point to some introductory material I'd be much grateful 



#2
Feb1212, 12:19 PM

P: 234

Wikipedia's article on "affine connection" has exactly this situation as a motivating example. But I don't think it's any less mathematically demanding than the one on holonomy, so that may not be helpful.
I thought about it for a while, and I believe I can answer your second question in the affirmative: any rotation of the (assume unit) sphere can be realized by rolling along a closed path in the plane (and I think that [itex]6\pi[/itex] is an upper bound on the length of the path). The way to see it is to ask a related question: (1) which points in the plane can I reach if I require the sphere to end in the same orientation it began with? If the answer is "all of them", then we can reduce the original problem a simpler question: (2) can we achieve any orientation by rolling along an arbitrary path? For (1), just notice that I can roll a distance of [itex]2\pi[/itex] along a straight line in any direction I like, and end up back in the original orientation (I've just done a full rotation about the axis parallel to the plane and perpendicular to travel). I can combine two such motions to reach any point within a radius of [itex]4\pi[/itex], and obviously this means I can reach any other point in the plane by similar means. So now, if I can roll along a nonclosed path to achieve the orientation I want, I can then close that path up with an orientationpreserving path, giving me a closed path that ends up with the desired orientation. So all that remains is (2) to show that we can always do that. Any rotation of the sphere has an axisangle description, i.e. it is specified by rotation by a certain angle around a particular axis. By rolling in a straight line, I can rotate by an arbitrary angle, around any axis which is parallel to the plane. And if I want to rotate around an axis that isn't planeparallel, it's obvious that there's another straightline path P I can roll along to make it become so. Then I rotate the desired amount around it, then I roll along the reverse of P (translated to my new position), and I'm done. The upper bound comes from the fact that I have to roll at most [itex]\pi/2[/itex] to bring my rotation axis parallel to the plane (in the case where it's the vertical axis), and that a roll by [itex]\pi[/itex] one way or the other is sufficient for any rotation around that axis. Then I roll at most [itex]\pi/2[/itex] again to put my axis back where it started, and then [itex]4\pi[/itex] to go home. I'd be astonished if there's not a better upper bound that doesn't involve such ugly (albeit easy to think about) paths. 


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