
#1
Apr2412, 12:51 AM

P: 63

1. The problem statement, all variables and given/known data
An elastic string is attached to A on a horizontal plane and a mass is attached to the other side of the rope.Then the rope is pulled to C and release.It engage in SHM from C to B and D to E and so on natural length = l extension = a max end points = E & C
2. Relevant equations 3. The attempt at a solution I know that it doesn't engage SHM from B to D as the rope has not exceeded its natural length at that time...From B to D it travels at a constant velocity...As the periodic time of the oscillation is the time that it takes to complete an oscillation,I think it must be 2t_{EC},but not sure maybe its 2(t_{ED}+t_{BC}). Actually I don't have an idea about the center if oscillation whether its A or B and D. And also amplitude.I think its DE or BC not AE as the SHM happens in only that area.. 



#2
Apr2412, 01:32 AM

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P: 11,416

Presumably the question would like you to consider the endtoend motion of the mass (between C and E) to comprise the SHM. If that is the case, then what strategy would you propose for finding the period?




#3
Apr2412, 01:56 AM

P: 63

I think that the period is 2t_{EC}
t_{EC}=t_{AD}+t_{DE} to find t_{AD} we can use SUVAT equations. and t_{DE}=(∏/2)/ω 



#4
Apr2412, 02:10 AM

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P: 11,416

Simple Harmonic Motion problem 



#5
Apr2412, 02:31 AM

P: 63

here ω is the angular velocity (dθ/dt)
With F=ma and Hooke's law,I can get a function like and calculate the period..any way the process is simple for me...But I want's to know, periodic time of the SHM Center if oscillation amplitude of the SHM Just please define them using letters in the image.. optional:




#6
Apr2412, 10:43 AM

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P: 11,416

The period of anything with a cycle is the time to start from a given state and return to that state. In this case pick a point on the trajectory of the mass and (such as point C) and find an expression in terms of l, a, M, and k (or ##\lambda## if you prefer) for time for the mass to travel from C to E and back to C.
For the center of oscillation I would need to know if there is a particular definition used in your coursework. The one I'm familiar with pertains to physical pendulums and is related to the Radius of Gyration for a pivoted pendulum. Otherwise I would make the obvious choice and say that it corresponds to the average position of mass during a period (point A). The amplitude of the oscillation should be obvious from the trajectory; what is the maximum displacement from the center of oscillation? 



#7
Apr2412, 11:09 AM

P: 63

Center of oscillation is defined as where acceleration is zero.So its B for C to B motion and D for E to D motion.
And the amplitude is DE for DE motion and BC for BC motion.. (as shown in examples of my coursework..) I don't know what it will be to the whole journey..And I think that we can't take such thing as whole journey but taking the two SHMs(BC & DM) separately maybe the right way... Am I correct.. 



#8
Apr2412, 11:31 AM

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P: 11,416





#9
Apr2412, 11:45 AM

P: 63

anyway..I have some another question.. We know at the center of oscillation the acceleration is zero (a=0).... no acceleration means no resultant force..If so...Is the center of oscillation ,a equilibrium position (a balanced position) ? 



#10
Apr2412, 11:54 AM

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P: 11,416





#11
Apr2412, 12:00 PM

P: 63

What about the last question I asked(Is the center of oscillation ,a equilibrium position (a balanced position) ?)..Its not about the question we discussed above..




#12
Apr2412, 12:10 PM

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#13
Apr2412, 12:34 PM

P: 63

So can u answer this...?
A mass is hanged by an elastic rope..So there's an extension in the rope and the mass is in its equilibrium(balanced) position(T=mg)...ok.. now the mass is pulled down to some length from that balanced position..Then releases... Now it asks to find the time when it passes the equilibrium position...I want to know whether the T=mg position is a=0(the center of SHM) position or not ? 



#14
Apr2412, 01:14 PM

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P: 11,416





#15
Apr2412, 01:19 PM

P: 63

got ya !




#16
Apr2512, 01:58 PM

P: 63

(Sorry if I'm making trouble...)
Is center of oscillation of any SHM ,in equilibrium ? We know that in the center of oscillation in SHMs of masses on a spring or a elastic string there's no any resultant force...so it in equilibrium.. But when we consider about the SHM of a simple pendulum or a mass that engage in uniform circular motion....there's a resultant force at their center of oscillation(Centripetal force).... So pls make this clear...thanks ! 



#17
Apr2512, 02:14 PM

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P: 11,416




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