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Rotational Motion

 
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Apr28-12, 07:43 AM   #1
 

Rotational Motion


Hi guys, I have a few doubts on Rotational Motion and hope someone can help me out.

This 3 formula is for finding angular velocity, angular acceleration and angular displacement right?
ω=ωi+αt
ω²=ωi²+2αδ
δ=ωit+1/2αt²



And this 3 formula is for finding the linear velocity/acceleration/displacement in a angular shape?
s=rδ
v=rω
α=rα



Thanks.
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Apr28-12, 07:48 AM   #2
 
If you have no problems on linear acceleration then then only thing that changes in rotational motion is that u becomes ω , a becomes α , x becomes θ .

In both of your questions , the answer is yes .
Apr28-12, 07:58 AM   #3
 
Thank you ZxcvbnM2000 for the reply.


I want to ask can I use this equation v=rω to find the angular velocity as well?
Apr28-12, 09:00 AM   #4
 

Rotational Motion


yes of course as long as you know the linear velocity and the radius ;p
Apr28-12, 09:33 AM   #5
 
Ok thank you for the explanation and help.

Out of topic abit, if a rock is thrown downward from the top of a building, the velocity I can set it as -ve or +ve, and usually people set it to +ve for the working to be easier, am I right?
Apr29-12, 03:24 PM   #6
 
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hi freshbox!
Quote by freshbox View Post
This 3 formula is for finding angular velocity, angular acceleration and angular displacement right?
ω=ωi+αt
ω²=ωi²+2αδ
δ=ωit+1/2αt²
only for constant acceleration (just like the linear case)
And this 3 formula is for finding the linear velocity/acceleration/displacement in a angular shape?
s=rδ
v=rω
a=rα
s=rδ works only for constant ω

the other two always work
Quote by freshbox View Post
… if a rock is thrown downward from the top of a building, the velocity I can set it as -ve or +ve, and usually people set it to +ve for the working to be easier, am I right?
yes, so long as you're careful to adjust the sign of g to match
May1-12, 05:49 AM   #7
 
thank you tiny-tim for the explanation.
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