Polymer Engineering question related to Von Mises yield criterion

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The discussion revolves around solving a proof question for extra credit related to material mechanics, specifically focusing on finding values A and B using two simultaneous equations. The first equation assumes uniaxial tension yielding, setting σ1 as the yield strength (fty) and σ2 and σ3 as zero. The second equation assumes uniaxial compression yielding, noting that for polymers, the yield strengths in tension (fty) and compression (fcy) differ, which is crucial for determining A. After calculating A and B, the next step is to analyze the hydrostatic case by setting σ1, σ2, and σ3 equal to σ and solving for σ. This approach highlights the importance of understanding material behavior under different stress conditions.
kennyyip
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It is a proof question. Does anyone can tell me how to do this question?question 22.2
it is the question for extra credit for my final exam.
thank you so much.
 

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You can find A and B with two simultaneously equations.
For the first equation assume uniaxial tension yielding - i.e. take σ1 as fty and σ2=σ3=0.
For the second equation assume uniaxial compression yielding. This is a polymer so it makes sense that fty and fcy would be different values - and they have to be different values otherwise you'd find that A=0.

Once you have A and B, then consider the hydrostatic case - i.e. take σ1=σ2=σ3=σ. Solve for σ.
 
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