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Normal/Tangential Force |
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| Jun18-12, 07:40 PM | #1 |
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Normal/Tangential Force
Hi. I have two questions
All contact forces are normal to the surface right? If there was no friction, there wouldn't be any tangential force? Thanks |
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| Jun18-12, 11:53 PM | #2 |
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The normal force is indeed always normal to whatever surface you are talking about. The frictional force is tangential to that surface, and is proportional to the Normal force in elementary analysis.
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| Jun19-12, 04:56 AM | #3 |
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| Jun19-12, 07:20 AM | #4 |
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Normal/Tangential Force
Thanks for the replies
What I want to know is if all tangential forces are due to friction. In a fast collision, the tangential force can be neglected? |
| Jun19-12, 10:03 AM | #5 |
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See for example motion on inclined plane. The gravity has a tangential component. The effect of tangential forces on the final momentum distribution may become important for collisions that are not "head-on". For example, throwing a ball towards a wall at an angle. If the ball-wall friction is large the tangential component of the momentum will decrease and the angle of "reflection" will be smaller than the angle of incidence. |
| Jun19-12, 11:53 AM | #6 |
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The thing you said about the ball is what I wanted to read. My teachers neglect the tangential component when we talk about collisions. Maybe that's because they are engineers. Edit: But if you see collision articles, they talk only about the force which is normal to the contact surface! (tangential neglected) Collision is considered fast so the tangential force might be very little? |
| Jun19-12, 01:54 PM | #7 |
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I mean, is there a tangential component of the momentum of the colliding object(s) or not? |
| Jun19-12, 02:24 PM | #8 |
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Collisions which produce torque, where the normal force is not in the direction of the center of mass, those have tangential force for sure right? |
| Jun19-12, 06:12 PM | #9 |
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Also, I don't think one can argue that the contact is too brief for the tangential force to matter. The maximum tangential force is proportional, at each instant, to the actual normal force, just as in normal static arrangements, and the tangential and normal forces operate over the same brief time period. If a ball radius R rebounds from a surface with speed V at θ to the normal, no sliding, I would think that the ball is now spinning at rate V sin(θ) / R. |
| Jun20-12, 04:03 AM | #10 |
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1. The ball may slide across the wall instead of rolling without slippage. This would tend to apply in, for instance, the case of a steel ball hitting a steel wall at a glancing angle. In the limit your spin rate omega(final) = omega(initial). 2. Rotational rebound. In my youth we used to play with "super balls". These were hard rubber balls that rebounded pretty efficiently (90 to 95% restitution). They were also sticky enough that they would catch immediately and roll without slipping. If you threw one of these at the floor and got a good spin on it you could watch it go into a back and forth bouncing pattern with the direction of rotation reversing at each bounce. In the limit your spin rate omega(final) = 2 V sin(θ) / R - omega(initial) The spin rate resulting from any actual collision could be expected to lie somewhere in this range. |
| Jun20-12, 05:59 AM | #11 |
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