Find the equivalent resistance of a circuit below

AI Thread Summary
The discussion focuses on calculating the equivalent resistance of a circuit with six 12-ohm resistors. The initial calculations by the user suggest an equivalent resistance of 20Ω, but other participants identify errors in the calculations, particularly in the handling of parallel resistor combinations. The correct approach involves recognizing that resistors in parallel require reciprocal calculations, leading to the need for adjustments in the user's equations. The final consensus emphasizes the importance of correctly applying parallel resistance formulas to arrive at the accurate equivalent resistance. The conversation highlights the collaborative effort to ensure accurate circuit analysis.
shashaeee
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Find the equivalent resistance of the circuit shown below. Each of the six resistors has a resistance of 12 ohm.
physics.jpg


I just want to make sure I calculated everything right. I don't have the solution available.

Labelling the resistors from my left to the right: R1, R2, R3, R4, R5(bottom), R6

What I did:

R5 + R6 = R56

1/R56 + 1/R4 = R456

R456 + R3 = R3456

1/R3456 + 1/R2 = R23456

R23456 + R1 = Req = 20Ω

Thanks!
 
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Your logic all looks correct to me. I don't have a calculator available, but your work looks fine and the answer seems reasonable.

Edit: The post below me is correct, I missed those errors.
 
Last edited:
shashaeee said:
1/R56 + 1/R4 = R456

No, 1/R56 + 1/R4 = 1/R456


1/R3456 + 1/R2 = R23456

No, 1/R3456 + 1/R2 = 1/R23456
 
The resistors are of equal value.
In calculation this value is substituted in the equations.
R5+R6=2R
Next the parallel resistor
2R.R/(2R+R)=2R/3
And the next configuration till R1
 
Thanks guys!
 

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